document.write( "Question 1036005: A company that manufacturers paint cans designed a can that has a radius or 3 inches and a volume of 83 cubic inches. For a new can design the company plans to keep the height the same and double the radius. What will be the affect on the can's volume? \n" ); document.write( "
Algebra.Com's Answer #650593 by stanbon(75887)\"\" \"About 
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A company that manufacturers paint cans designed a can that has a radius or 3 inches and a volume of 83 cubic inches. For a new can design the company plans to keep the height the same and double the radius. What will be the affect on the can's volume?
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\n" ); document.write( "Original can DATA
\n" ); document.write( "Volume = pi*r^2*h
\n" ); document.write( "83 = pi*3^2*h\r
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\n" ); document.write( "New design DATA
\n" ); document.write( "V = pi*(2*3)^2*h
\n" ); document.write( "Rearrange::
\n" ); document.write( "V = pi*3^2*2^2*h
\n" ); document.write( "V = pi(3^2)h *2^2
\n" ); document.write( "V = 83*4
\n" ); document.write( "Ans:: The volume will be multiplied by 4.
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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