document.write( "Question 1035980: How many gallons of a 70% antifreeze solution must be mixed with 90 gallons of 25% antifreeze to get a mixture that is 60% antifreeze? Use the six-step method. can you help me do this type proble? \n" ); document.write( "
Algebra.Com's Answer #650574 by stanbon(75887) ![]() You can put this solution on YOUR website! How many gallons of a 70% antifreeze solution must be mixed with 90 gallons of 25% antifreeze to get a mixture that is 60% antifreeze? Use the six-step method. can you help me do this type proble? \n" ); document.write( "------ \n" ); document.write( "Equation:: \n" ); document.write( "anti + anti = anti \n" ); document.write( "----- \n" ); document.write( "0.70x + 0.25*90 = 0.60(x + 90) \n" ); document.write( "-------- \n" ); document.write( "70x + 25*90 = 60x + 60*90 \n" ); document.write( "------ \n" ); document.write( "10x = 35*90 \n" ); document.write( "x = 9*35 \n" ); document.write( "x = 315 gallons (amt. of 70% solution needed) \n" ); document.write( "--------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "------------- \n" ); document.write( " |