document.write( "Question 1035980: How many gallons of a 70​% antifreeze solution must be mixed with 90 gallons of 25​% antifreeze to get a mixture that is 60​% ​antifreeze? Use the​ six-step method. can you help me do this type proble? \n" ); document.write( "
Algebra.Com's Answer #650574 by stanbon(75887)\"\" \"About 
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How many gallons of a 70​% antifreeze solution must be mixed with 90 gallons of 25​% antifreeze to get a mixture that is 60​% ​antifreeze? Use the​ six-step method. can you help me do this type proble?
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\n" ); document.write( "Equation::
\n" ); document.write( "anti + anti = anti
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\n" ); document.write( "0.70x + 0.25*90 = 0.60(x + 90)
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\n" ); document.write( "70x + 25*90 = 60x + 60*90
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\n" ); document.write( "10x = 35*90
\n" ); document.write( "x = 9*35
\n" ); document.write( "x = 315 gallons (amt. of 70% solution needed)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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