document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1035945>Question 1035945</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Three times Fred’s age plus four times Jane's age equals 71. Fred's age is also three less than two times Jane's age.\r<BR>\n" );
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document.write( "How old is Fred?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #650540 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=650540\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call their ages, f and j.  We can then write<BR>\n" );
document.write( "3f + 4j = 71<BR>\n" );
document.write( "f = 2j - 3<BR>\n" );
document.write( "Now substitute the second one into the first one...we get...<BR>\n" );
document.write( "3(2j - 3) + 4j = 71<BR>\n" );
document.write( "6j - 9 + 4j = 71<BR>\n" );
document.write( "10j = 80<BR>\n" );
document.write( "j = 8<BR>\n" );
document.write( "f = 2(8) - 3 = 13 </SPAN>\n" );
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