document.write( "Question 1035916: A boy age is 1/4 the age of his dad their total age less than 80yrs, by solving an inequation, find 1.boy age
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document.write( " 2.father age \n" );
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Algebra.Com's Answer #650535 by ashishtayal(3)![]() ![]() ![]() You can put this solution on YOUR website! Let father age = x years \n" ); document.write( "thus, boy age = x/4 years\r \n" ); document.write( "\n" ); document.write( "x + x/4 < 80 \n" ); document.write( "5x/4 < 80 \n" ); document.write( "5x < 320 \n" ); document.write( "x<64\r \n" ); document.write( "\n" ); document.write( "So, possible solutions are \n" ); document.write( "Father's age = 60 years, Boy's age = 15 years \n" ); document.write( "Father's age = 56 years, Boy's age = 14 years \n" ); document.write( "Father's age = 52 years, Boy's age = 13 years \n" ); document.write( "Father's age = 48 years, Boy's age = 12 years \n" ); document.write( "Father's age = 44 years, Boy's age = 11 years \n" ); document.write( "Father's age = 40 years, Boy's age = 10 years \n" ); document.write( "Father's age = 36 years, Boy's age = 9 years \n" ); document.write( "Father's age = 32 years, Boy's age = 8 years \n" ); document.write( "Father's age = 28 years, Boy's age = 7 years \n" ); document.write( "Father's age = 24 years, Boy's age = 6 years \n" ); document.write( "Father's age = 20 years, Boy's age = 5 years \n" ); document.write( " |