document.write( "Question 1035902: The length of the triangle is 1 cm more than the width. If the perimeter of the rectangle is 6 cm, then what are the dimensions of the rectangle.
\n" ); document.write( "The width of a rectangle is 2/3 of its length. Find its length if the perimeter is 80 cm. Find its dimensions.
\n" ); document.write( "Half the perimeter of a rectangle is 51 cm. If the difference between the length and the width is 13 cm then find the area of the rectangle.
\n" ); document.write( "Thank you so much for the help. This will help me in my assignment.
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Algebra.Com's Answer #650523 by ikleyn(52798)\"\" \"About 
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\n" ); document.write( "The length of the \"highlight%28cross%28triangle%29%29\" rectangle is 1 cm more than the width. If the perimeter of the rectangle is 6 cm, then what are the dimensions of the rectangle.
\n" ); document.write( "The width of a rectangle is 2/3 of its length. Find its length if the perimeter is 80 cm. Find its dimensions.
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\n" ); document.write( "\n" ); document.write( "1. The length of the rectangle is 1 cm more than the width.
\n" ); document.write( "    If the perimeter of the rectangle is 6 cm, then what are the dimensions of the rectangle.\r
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document.write( "Let L be the rectangle length ans W be the rectangle width. Then\r\n" );
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document.write( "L - W = 1,     (1)   ( \"The length of the rectangle is 1 cm more than the width\" )\r\n" );
document.write( "L + W = 3.     (2)   ( 3 is half of 6, half of the perimeter. Do you understand why this equation (2) is true?  It is the key! )\r\n" );
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document.write( "Now, to solve the system (1), (2), add the equations (1) and (2). You will get\r\n" );
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document.write( "2L = 1 + 3 = 4,   hence,   L = \"4%2F2\" = 2.  So, you just found the length L.\r\n" );
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document.write( "Next, find W from equation (2): W = 3 - L = 3 - 2 = 1.\r\n" );
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document.write( "The problem is solved.\r\n" );
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document.write( "Answer. L = 2, W = 1.\r\n" );
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