document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1035820>Question 1035820</A>: <I><SPAN STYLE=\"word-break: break-all;\"> larry mitchell invested part of his $33,000 advance at 2% annual simple interest and the rest at 9% annual simple interest. the yearly total from both was $1,010. Find the amount at each rate.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #650449 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel555><B>jorel555(1290)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel555><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=650449\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let n= amount invested at 2%. Then<BR>\n" );
document.write( ".02n+.09(33000-n)=1010<BR>\n" );
document.write( ".02n+2970-.09n=1010<BR>\n" );
document.write( ".07n=1960<BR>\n" );
document.write( "n=1960/.07=28000 invested at 2%, 5000 invested at 9%!!!!!!!!!!! </SPAN>\n" );
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