document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1035788>Question 1035788</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Use the substitution method to solve m - n = 7 and 3m + 2n = 6. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #650427 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=650427\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Okay, from<BR>\n" );
document.write( "m - n = 7 and 3m + 2n = 6,<BR>\n" );
document.write( "we solve the first one for m,<BR>\n" );
document.write( "m = n + 7 \and substitute that into the second one, like this...<BR>\n" );
document.write( "3(n+7) + 2n = 6<BR>\n" );
document.write( "3n + 21 + 2n = 6<BR>\n" );
document.write( "5n + 21 = 6<BR>\n" );
document.write( "5n = -15<BR>\n" );
document.write( "n = -3<BR>\n" );
document.write( "Now m = n+7 = -3 + 7 = 4 </SPAN>\n" );
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