document.write( "Question 1035765: I have to resolve the equation in the interval 0 ≤ Ø < 2x. sin Ø = √2 - cos Ø \n" ); document.write( "
Algebra.Com's Answer #650417 by Alan3354(69443)\"\" \"About 
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sin Ø = sqrt(2) - cos Ø
\n" ); document.write( "sin^2 = 2 - sqrt(8)cos + cos^2
\n" ); document.write( "1 - cos^2 = 2 - sqrt(8)cos + cos^2
\n" ); document.write( "2cos^2 - sqrt(8)cos + 1 = 0
\n" ); document.write( "disc = b^2 - 4ac = 8 - 8 = 0\r
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\n" ); document.write( "cos = -b/2a = 2sqrt(2)/4 = sqrt(2)/2
\n" ); document.write( "Ø = pi/4, 0< Ø < 2pi (not 2x)
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