document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1035767>Question 1035767</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a/(a-1)=1-(1/a)\r<BR>\n" );
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document.write( "how do i solve this equation and check for extraneous solutions? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #650416 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=650416\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a/(a-1)=1-(1/a) <BR>\n" );
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document.write( "a/(a-1)= (a-1)/a; the second part is (a/a)-(1/a) or 1- (1/a)<BR>\n" );
document.write( "multiply both sides by the common denominator a(a-1)<BR>\n" );
document.write( "a^2=(a-1)^2<BR>\n" );
document.write( "don't take the square root <BR>\n" );
document.write( "a^2=a^2-2a+1<BR>\n" );
document.write( "2a=1<BR>\n" );
document.write( "a=(1/2) ANSWER<BR>\n" );
document.write( "(1/2)/(-1/2)=1-(1/(1/2)), the second part is 1-2=-1<BR>\n" );
document.write( "-1=1-2=-1<BR>\n" );
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