document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1035765>Question 1035765</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I have to resolve the equation in the interval 0 &#8804; Ø < 2x. sin Ø = &#8730;2 - cos Ø </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #650411 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=650411\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> By looking at it, I can see that the angle needed is 45 degrees...to verify it, I went and graphed<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y+=+sin%28x%29+%2B+cos%28x%29+ ALIGN=MIDDLE  ALT=\"y+=+sin%28x%29+%2B+cos%28x%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "and found that the graph only reaches sqrt(2) at 45 degrees... </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );