document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=12859>Question 12859</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What are 3 consecutive numbers with the sum of 600? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #6504 by </B><A HREF=/tutors/aboutme.mpl?userid=chicosgurrl><B>chicosgurrl(2)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=chicosgurrl><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=6504\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First lets choose a variable for the three unknown numbers. They are consecutive which means that they are in ascending(going up)order (for example..1,2,3,4)\r<BR>\n" );
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document.write( "So Lets choose X for the first number.<BR>\n" );
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document.write( "since the next number is consecutive to X, it will be one number more than X which is written as X+1<BR>\n" );
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document.write( "So, Let the second number = X+1 (that is just the first unknown number plus 1)<BR>\n" );
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document.write( "now the next nuber is still consecutive so it's just X+1+1 OR simplify to X+2<BR>\n" );
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document.write( "NOW, to recap, our unknown numbers are:<BR>\n" );
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document.write( " X<BR>\n" );
document.write( "(X+1)<BR>\n" );
document.write( "(X+2)<BR>\n" );
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document.write( "and we know that the sum of these three numbers is equal to 600.<BR>\n" );
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document.write( "so write as:           X+(X+1)+(X+2)=600\r<BR>\n" );
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document.write( "Simplify:                       3X+3=600<BR>\n" );
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document.write( "Get the x on one side by subtracting 3 from both sides:      <BR>\n" );
document.write( "                                  3x+3=600<BR>\n" );
document.write( "..                                     -3=-3         <BR>\n" );
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document.write( ".After that it becomes: 3x=597<BR>\n" );
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document.write( "Now, get the X by itself by dividing both sides by 3:<BR>\n" );
document.write( "                           3x=597 <BR>\n" );
document.write( " ..                           X=199\r<BR>\n" );
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document.write( " now you know x, so plug it in   X=199<BR>\n" );
document.write( "                                 X+1 is the same as 199+1 which is =200<BR>\n" );
document.write( "                                 X+2 is the same as 199+2 which is 201\r<BR>\n" );
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document.write( "so the answers are: 199, 200, 201<BR>\n" );
document.write( "they are consecutive and the sum of the three is =600\r<BR>\n" );
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document.write( "I hope this helps. =)<BR>\n" );
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