document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1035757>Question 1035757</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The age of a father is 10 less than the sum of the ages of his two sons. 7 years ago his age was 3 times the sum of the ages of his sons find their present ages  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #650393 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=650393\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let f be the age of the father NOW and s be the sum of his sons' ages NOW...then we write<BR>\n" );
document.write( "f = s - 10  and seven years ago<BR>\n" );
document.write( "f - 7 = 3(s - 7)<BR>\n" );
document.write( "Now substitute and get<BR>\n" );
document.write( "s-10 - 7 = 3(s - 7)<BR>\n" );
document.write( "s - 17 = 3s - 21<BR>\n" );
document.write( "Subtract s and add 21...we get<BR>\n" );
document.write( "2s = 4<BR>\n" );
document.write( "s = 2<BR>\n" );
document.write( "But that is impossible.<BR>\n" );
document.write( "Please repost the problem.<BR>\n" );
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