document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1035729>Question 1035729</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Could you tell me if I'm on the right track with this question? Thank you.\r<BR>\n" );
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document.write( "A picture frame measures 40cm by 30cm and 704cm^2 of picture shows. Find the width of the frame.\r<BR>\n" );
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document.write( "(30-2x)(40-2x)=704<BR>\n" );
document.write( "4x^2-140x+1200=704<BR>\n" );
document.write( "4x^2-140x+496=0<BR>\n" );
document.write( "(x-4)(x-31)<BR>\n" );
document.write( "x=4 or x=31\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #650380 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=650380\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> if you are assuming that the border around the picture is the same size, then you are correct.<BR>\n" );
document.write( "you got x = 4 or x = 31.<BR>\n" );
document.write( "x can't be 31 because the length and the width would be negative, which is not possible.<BR>\n" );
document.write( "therefore, x = 4 is the only possible solution.<BR>\n" );
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