document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1035725>Question 1035725</A>: <I><SPAN STYLE=\"word-break: break-all;\"> im not sure if i selected the right topic but i need to solve this math equation by completing the square the problem is -3x squared+18x=-30 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #650375 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=650375\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> -3x^2 + 18x = -30<BR>\n" );
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document.write( "divide both sides of = by -3<BR>\n" );
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document.write( "x^2 - 6x = 10<BR>\n" );
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document.write( "divide -6 by 2 and square it, then add result to both sides of =<BR>\n" );
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document.write( "x^2 - 6x + 9 = 10 + 9<BR>\n" );
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document.write( "(x - 3)^2 = 19<BR>\n" );
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document.write( "now take square root of both sides of =<BR>\n" );
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document.write( "x - 3 = + or - square root(19)<BR>\n" );
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document.write( "x = 3 + square root(19)<BR>\n" );
document.write( "x = 3 - square root(19)<BR>\n" );
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