document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1035688>Question 1035688</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a rectangle has an area of 108 cm to the second power.  Its width is 3 cm longer than its length.  Find the dimensions of the rectangle.  (a labeled diagram and algebraic solution are required to receive full credit).  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #650356 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39617)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=650356\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> w for width and L for length;<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=system%28wL=108%2Cw=3%2BL%29 ALIGN=MIDDLE  ALT=\"system%28wL=108%2Cw=3%2BL%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Substitute and solve the resulting quadratic equation and then use it to evaluate the other variable.\r<BR>\n" );
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document.write( "The number, 108, is not to the second power.  Read the measure carefully.  An area is being described.  The number tells information about the area.  A linear dimension unit, length, is to the second power - not the number. </SPAN>\n" );
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