document.write( "Question 1035668: A1. Let f be a one-to-one function whose inverse function is given by the formula\r
\n" ); document.write( "\n" ); document.write( "\"f%5E%28-1%29%28x%29=x%5E5%2B2x%5E3%2B3x%2B1\"\r
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\n" ); document.write( "\n" ); document.write( "(a) Compute \"f%5E-1%281%29\" and \"f%281%29\"
\n" ); document.write( "(b) Compute the value of \"x%5B0%5D\" such that \"f%28x%5B0%5D%29+=+1\".
\n" ); document.write( "(c) Compute the value of \"y%5B0%5D\" such that \"f%5E-1%28y%5B0%5D%29=1\".\r
\n" ); document.write( "\n" ); document.write( "Thankyou for looking over! Steps and instructions will be appreciate.
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Algebra.Com's Answer #650338 by robertb(5830)\"\" \"About 
You can put this solution on YOUR website!
(a) \"f%5E-1%281%29+=+1%5E5%2B2%2A1%5E3%2B3%2A1%2B1+=+7\".
\n" ); document.write( "To find f(1), substitute f(1) into \"f%5E%28-1%29%28x%29\"\r
\n" ); document.write( "\n" ); document.write( "==> \"1+=+f%5E-1%28f%281%29%29=%28f%281%29%29%5E5%2B2%2A%28f%281%29%29%5E3%2B3%2Af%281%29%2B1\"
\n" ); document.write( "==> ==> \"highlight%28f%281%29+=+0%29\", since \"%28f%281%29%29%5E4%2B2%2A%28f%281%29%29%5E2%2B3+%3E+0\".\r
\n" ); document.write( "\n" ); document.write( "(b) \"f%28x%5B0%5D%29+=+1\" ==> \"x%5B0%5D+=+f%5E%28-1%29%281%29+=+7\".\r
\n" ); document.write( "\n" ); document.write( "(c) \"f%5E-1%28y%5B0%5D%29=1\" ==> \"f%5E-1%28y%5B0%5D%29=%28y%5B0%5D%29%5E5%2B2%2A%28y%5B0%5D%29%5E3%2B3%2Ay%5B0%5Dx%2B1+=+1\"\r
\n" ); document.write( "\n" ); document.write( "==> \"%28y%5B0%5D%29%5E5%2B2%2A%28y%5B0%5D%29%5E3%2B3%2Ay%5B0%5D+=+0\" ==> \"%28y%5B0%5D%29%28+%28y%5B0%5D%29%5E4%2B2%2A%28y%5B0%5D%29%5E2%2B3+++++++++++++++%29+=+0\" ==> \"highlight%28y%5B0%5D+=+0%29\". (This is basically the same computation we had in the latter half of part (a).
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