document.write( "Question 89454: I have a problem that has thrown me for a loop. I am to find all values of y such that the distance between (3,y) and (-2,9) is 12. I tried to solve this problem by using the distance formula (X1,Y1)and (X2,Y2). Which looks like this d=the square root of (X2-X1)2 + (Y2-Y1)2 ***this is all under the square root symble and the 2 are squares**
\n" ); document.write( "(-2-3)2+(3-y)2 remember the 2's are sqrares and the problem is under the sqrare root symbole
\n" ); document.write( "(5)2+ (3-y)2
\n" ); document.write( "100+9-y2
\n" ); document.write( "109-Y2
\n" ); document.write( "I'm not sure if I am on the right path. Please help!
\n" ); document.write( "(sorry i do not know how to put the root symbole or make the 1 by the X and Y small on the computer) \n" ); document.write( "

Algebra.Com's Answer #65031 by stanbon(75887) $\"\"$ $\"About$

You can put this solution on YOUR website!
find all values of y such that the distance between (3,y) and (-2,9) is 12.
\n" ); document.write( "---------
\n" ); document.write( "d = sqrt((3--2)^2 + (y-9)^2)
\n" ); document.write( "12 = sqrt( 25 + (y-9)^2)
\n" ); document.write( "144 = 25 + (y-9)^2
\n" ); document.write( "119 = (y-9)^2
\n" ); document.write( "y = sqrt119 +9 or y = -sqrt119+9
\n" ); document.write( "y=19.909 or y= -1.909
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\n" ); document.write( "Cheers,
\n" ); document.write( "stan H. \n" ); document.write( "

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