document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1035658>Question 1035658</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The area of a rectangular floor is 105 square feet. if its length is 1 more than twice its width, find the length and width. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #650300 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=650300\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Area A = LW = 105<BR>\n" );
document.write( "We also have L = 2W + 1.<BR>\n" );
document.write( "Now substitute and get<BR>\n" );
document.write( "(2W+1)W = 105<BR>\n" );
document.write( "2W^2 + W - 105 = 0<BR>\n" );
document.write( "Now factor and solve<BR>\n" );
document.write( "(2W + 15)(W - 7) = 0<BR>\n" );
document.write( "so that <BR>\n" );
document.write( "W = 7 feet and<BR>\n" );
document.write( "L = 2W + 1 = 15 feet </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );