document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1035646>Question 1035646</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the sum of the seventh terms of a linear sequence is 38 and the ninth term is 37. find the sequence ?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #650288 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=650288\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a7=a1+6d=38<BR>\n" );
document.write( "a9=a1+8d=37<BR>\n" );
document.write( "subtract the second from the first<BR>\n" );
document.write( "-2d=1<BR>\n" );
document.write( "d=(-1/2)<BR>\n" );
document.write( "substitute back in<BR>\n" );
document.write( "38=a1+-3; a1=41<BR>\n" );
document.write( "a7=38<BR>\n" );
document.write( "a9=37<BR>\n" );
document.write( "41+(-1/2)an is the sequence<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );