document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1035603>Question 1035603</A>: <I><SPAN STYLE=\"word-break: break-all;\"> It took a crew 4h 30m to row 8km upstream and back again. If the rate of flow of the stream was 7 km/h, what was the rowing speed of the crew in still water? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #650274 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel555><B>jorel555(1290)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel555><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=650274\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If the distance was 8 km each way, then:<BR>\n" );
document.write( "8/(x+7)+8/(x-7)=9/2 hrs.<BR>\n" );
document.write( "16/(x+7)+16/(x-7)=9<BR>\n" );
document.write( "16(x-7)+16(x+7)=9(x^2-49)<BR>\n" );
document.write( "16x-112+16x+112=9x^2-441<BR>\n" );
document.write( "9x^2-32x-441=0<BR>\n" );
document.write( "Factoring 9x^2-32x-441 we get (9x+49)(x-9).  So our answer is 9 km/h as the speed of the rowing crew in still water!!!!!!! </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );