document.write( "Question 89451: Please help me on how to figure out the vertex of the equation 2y=x2(this is x squared)-2x-5. \n" ); document.write( "
Algebra.Com's Answer #65025 by stanbon(75887)\"\" \"About 
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Please help me on how to figure out the vertex of the equation 2y=x2(this is x squared)-2x-5.
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\n" ); document.write( "2y=x^2-2x-5
\n" ); document.write( "Complete the square on the x-terms and keep the equation balanced:
\n" ); document.write( "2y+5+1 = x^2-2x+1
\n" ); document.write( "2(y+3) = (x-1)^2
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\n" ); document.write( "The vertex is at (1,-3)
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\n" ); document.write( "Another way to find it:
\n" ); document.write( "y = (1/2)x^2-x-(5/2)
\n" ); document.write( "The vertex occus when x=(-b)/(2a) = 1/(2*(1/2)) = 1/1=1
\n" ); document.write( "Solve for y to get the y coordinate:
\n" ); document.write( "y = (1/2)1^2-1-(5/2) = (1/2)-1(-5/2) = -6/2 = -3
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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