document.write( "Question 1035576: In a triangle ABC ,AB=12cms , BC=8cms, CA=10cms .An incircle is drawn inside the triangle
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Algebra.Com's Answer #650219 by ikleyn(52786)\"\" \"About 
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\n" ); document.write( "In a triangle ABC ,AB=12cms , BC=8cms, CA=10cms. An incircle is drawn inside the triangle touching the sides AB, BC and CA
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\r\n" ); document.write( "I have found an appropriate figure from my archive  (see on the right).\r\n" ); document.write( "Although it is not in the scale, it is not so important for the solution.                 \r\n" ); document.write( "\r\n" ); document.write( "The names a, b and c are just employed for the side lengths:\r\n" ); document.write( "|AB| = c = 12 cm, |BC| = a = 8 cm, and |AC| = b = 10 cm.\r\n" ); document.write( "\r\n" ); document.write( "So we introduce d = |AD|= |AF|, e = |BE| = |BD| and f = |CF| = |CE|.\r\n" ); document.write( "\r\n" ); document.write( "I hope you are familiar with the fact that tangent lines to a circle drawn \r\n" ); document.write( "from the outside point, are congruent, and therefore doubled equalities \r\n" ); document.write( "in the line above do not arose questions.\r\n" ); document.write( "\r\n" ); document.write( "We have this system of equations\r\n" ); document.write( "\r\n" ); document.write( "|AD| + |BD| = |AB|, d + e = a, (1)\r\n" ); document.write( "|BE| + |CE| = |BC|, or, which is the same, e + f = b. (2)\r\n" ); document.write( "|AF| + |CF| = |AC| d + f = c. (3)\r\n" ); document.write( "\r\n" ); document.write( "By adding equations (1), (2) and (3), you get\r\n" ); document.write( "\r\n" ); document.write( "2(d + e + f) = a + b + c, or d + e + f = \"%28a+%2B+b+%2B+c%29%2F2\". (4)\r\n" ); document.write( " \r\n" ); document.write( "\r\n" ); document.write( "
Now distract equation (1) from (4). You will get f = \"%28a+%2B+b+%2B+c%29%2F2+-+a\" = \"%28-a%2Bb%2Bc%29%2F2\". (5)\r\n" ); document.write( "\r\n" ); document.write( "Next, distract equation (2) from (4). You will get d = \"%28a+%2B+b+%2B+c%29%2F2+-+b\" = \"%28a-b%2Bc%29%2F2\". (6)\r\n" ); document.write( "\r\n" ); document.write( "Similarly, distract equation (3) from (4). You will get e = \"%28a+%2B+b+%2B+c%29%2F2+-+c\" = \"%28a%2Bb-c%29%2F2\". (7)\r\n" ); document.write( "\r\n" ); document.write( "Now substitute (plug in) the given numerical data into equations (5), (6) and (7). You will get\r\n" ); document.write( "\r\n" ); document.write( "f = \"%28-8%2B10%2B12%29%2F2\" = 7 cm, d = \"%288-10%2B12%29%2F2\" = 5 cm, e = \"%288%2B10-12%29%2F2\" = 3 cm.\r\n" ); document.write( "\r\n" ); document.write( "Answer. AF = d = 5 cm, BD = e = 3 cm, and CE = f = 7 cm.\r\n" ); document.write( "
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