document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=12915>Question 12915</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how would you solve a problem such as -7a=-12a-65? i dont understand this\r<BR>\n" );
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document.write( "josh </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #6502 by </B><A HREF=/tutors/aboutme.mpl?userid=kusha><B>kusha(21)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=kusha><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=6502\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> This is very basic and perhsps that is why no one is even touching this prolem. U should take the terms of x on one side ( & i hope u know that u need to change the signs wen u do so) and then solve for x \r<BR>\n" );
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document.write( "in this case -7A + 12A  = 65 <BR>\n" );
document.write( "5A = 65 <BR>\n" );
document.write( "thus A = 13\r<BR>\n" );
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document.write( "But u really need specific lessons for upgrading ur knowledge </SPAN>\n" );
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