document.write( "Question 1035556: Hello! I've tried solving this problem multiple times but I'm not sure if I've gotten the right answer or if I was doing it right. \r
\n" ); document.write( "\n" ); document.write( "Solve: \"%287x%2B1%29%2F%28x%5E2-8x%2B15%29%2B3x%2F%28x-5%29=-1%2F%28x-3%29\"\r
\n" ); document.write( "\n" ); document.write( "This is my work: First off, I marked that x cannot equal 5 or 3, because of how(x-3) and (x-5) are in the denominator and I can't have 0 in the denominator. I turned it into \"%287x%2B1%29%2F%28x-5%29%28x-3%29%2B3x%2F%28x-5%29=-1%28x-3%29\" I noticed that after I factored out \"x%5E2-8x%2B15\" I could rationalize the denominator to (x-5)(x-3) by multiplying 3x/(x-5) with (x-3) and -1/(x-3) with (x-5) and cancel it all out to just end up with \"%287x%2B1%29%2B3x%28x-3%29=-1%28x-5%29\". Next, I simplified it down to \"7x%2B1%2B3x%5E2-9x=-x%2B5\" to \"3x%5E2-x-4=0\". I didn't know if I could factor it out anymore mentally, so I chose my safest bet which was using the quadratic formula to get x=4/3 and x=-1. Those two answers would work because it's not 5 or 3 (because then it would equal 0). Am I right? Or did I do something wrong? I hope I was clear enough and I would really appreciate the help! \n" ); document.write( "
Algebra.Com's Answer #650196 by ikleyn(52776)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "Hello! I've tried solving this problem multiple times but I'm not sure if I've gotten the right answer or if I was doing it right. \r
\n" ); document.write( "\n" ); document.write( "Solve: \"%287x%2B1%29%2F%28x%5E2-8x%2B15%29%2B3x%2F%28x-5%29=-1%2F%28x-3%29\"\r
\n" ); document.write( "\n" ); document.write( "This is my work: \r
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document.write( "First off, I marked that x cannot equal 5 or 3, because of how(x-3) and (x-5) are in the denominator and \r\n" );
document.write( "I can't have 0 in the denominator. \r\n" );
document.write( "\r\n" );
document.write( "I turned it into \"%287x%2B1%29%2F%28x-5%29%28x-3%29%2B3x%2F%28x-5%29=-1%28x-3%29\"    ( <<<--- actually, right side is \"-1%2F%28x-3%29\", but I consider your error as a typo here )\r\n" );
document.write( "\r\n" );
document.write( "I noticed that after I factored out \"x%5E2-8x%2B15\" I could rationalize the denominator to (x-5)(x-3) by multiplying 3x/(x-5) \r\n" );
document.write( "\r\n" );
document.write( "with (x-3) and -1/(x-3) with (x-5) and cancel it all out to just end up with \"%287x%2B1%29%2B3x%28x-3%29=-1%28x-5%29\".           <<<--- CORRECT!\r\n" );
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document.write( "Next, I simplified it down to \"7x%2B1%2B3x%5E2-9x=-x%2B5\" to \"3x%5E2-x-4=0\".                      <<<--- CORRECT!\r\n" );
document.write( "\r\n" );
document.write( "I didn't know if I could factor it out anymore mentally, so I chose my safest bet which was using \r\n" );
document.write( "the quadratic formula to get x=4/3 and x=-1.                                                                     <<<--- CORRECT!\r\n" );
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document.write( "Those two answers would work because it's not 5 or 3 (because then it would equal 0).                            <<<--- CORRECT!\r\n" );
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document.write( "Am I right? Or did I do something wrong? I hope I was clear enough and I would really appreciate the help!    <<<---  You are right. No error. At least, I do not see it.\r\n" );
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