document.write( "Question 89425: For the quadratic function Q(x)=x^2+5x-36, determine the exact value of the minimum. \n" ); document.write( "
Algebra.Com's Answer #65015 by scott8148(6628)\"\" \"About 
You can put this solution on YOUR website!
the minimum value (or the maximum value if x^2 was negative) lies on the axis of symmetry\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "the equation for the axis of symmetry is x=-b/2a ... in this case, x=-5/2\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "to find the value for the minimum, just plug into the equation ... Q(x)=(-5/2)^2+5(-5/2)-36 ... Q(x)=-42.25
\n" ); document.write( "
\n" );