document.write( "Question 1035400: An Office Supply company sells x permanent markers per year @ $ p per marker.\r
\n" ); document.write( "\n" ); document.write( "The price demand equation for these markers is: P = 10-0.0001x\r
\n" ); document.write( "\n" ); document.write( "The total annual cost of manufacturing X permanent markers for the office supply company is: C(x) = 5000 + 2x\r
\n" ); document.write( "\n" ); document.write( "What is the company's maximum profit?
\n" ); document.write( "What should the company charge for each permanent marker?
\n" ); document.write( "How many markers should the company produce?
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Algebra.Com's Answer #650118 by robertb(5830)\"\" \"About 
You can put this solution on YOUR website!
The total revenues would be \r
\n" ); document.write( "\n" ); document.write( "\"R%28x%29+=+x%2810-0.0001x%29\"\r
\n" ); document.write( "\n" ); document.write( "==> Total profits would be \"P%28x%29+=+R%28x%29+-+C%28x%29+=+-010x+-+5000+-+2x+=+-0.0001x%5E2+%2B+8x+-5000\"\r
\n" ); document.write( "\n" ); document.write( "To maximize profits, the company should produce \"x+=+-b%2F%282a%29+=+-8%2F%282%2A-0.0001%29\" = 40,000 markers.\r
\n" ); document.write( "\n" ); document.write( "The company should charge 10 - 0.0001*40,000 = $6 for each marker.\r
\n" ); document.write( "\n" ); document.write( "The company's maximum profit is \"P%2840000%29+=+-0.0001%2A40000%5E2+%2B+8%2A40000+-5000+\" = $155,000.\r
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