document.write( "Question 1035372: 1. S.R
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Algebra.Com's Answer #650116 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!

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document.write( "1.  S & R\r\n" );
document.write( "2.  S -> X\r\n" );
document.write( "3.  X -> ~R  | :. (X & R) & (~R v W)\r\n" );
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document.write( "Contradictory premises.  \r\n" );
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document.write( "4  R         1 Conjunction Elimination\r\n" );
document.write( "5  S         1 Conjunction Elimination\r\n" );
document.write( "6  X         5, 2 Modus Ponens\r\n" );
document.write( "7  ~R        6, 3 Modus Ponens\r\n" );
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document.write( "7 contradicts 4\r\n" );
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\n" ); document.write( "John
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\n" ); document.write( "My calculator said it, I believe it, that settles it
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