document.write( "Question 1035372: 1. S.R
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document.write( "2. S>X
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document.write( "3. X>~R /:. (X.S).(~RvW) \n" );
document.write( "
Algebra.Com's Answer #650116 by solver91311(24713)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( " \r\n" ); document.write( "1. S & R\r\n" ); document.write( "2. S -> X\r\n" ); document.write( "3. X -> ~R | :. (X & R) & (~R v W)\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Contradictory premises. \r\n" ); document.write( "\r\n" ); document.write( "4 R 1 Conjunction Elimination\r\n" ); document.write( "5 S 1 Conjunction Elimination\r\n" ); document.write( "6 X 5, 2 Modus Ponens\r\n" ); document.write( "7 ~R 6, 3 Modus Ponens\r\n" ); document.write( "\r\n" ); document.write( "7 contradicts 4\r\n" ); document.write( " \n" ); document.write( "John \n" ); document.write( " \n" ); document.write( "My calculator said it, I believe it, that settles it \n" ); document.write( " ![]() \n" ); document.write( " |