document.write( "Question 1035432: Consider three consecutive odd integers. The sum of the first integer and 2 times the second is 54 more than the third. Find the integers. \n" ); document.write( "

Algebra.Com's Answer #650087 by jorel555(1290) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let's call the first integer n. The next two odd integers are n+2, and n+4. Then:
\n" ); document.write( "n+2(n+2)-54=(n+4)
\n" ); document.write( "n+2n+4-54=n+4
\n" ); document.write( "2n=54
\n" ); document.write( "n=27
\n" ); document.write( "n+2=29
\n" ); document.write( "n+4=31!!!!!! \n" ); document.write( "

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