document.write( "Question 1035397: John is deciding between two jobs. One promises convenient hours and is closer to his
\n" ); document.write( "home. The other pays $2.25 more per hour, and John would earn $1,000 in 10 hours less
\n" ); document.write( "than it will take him to earn $900 at the first job. What is the hourly wage for each job? \n" ); document.write( "
Algebra.Com's Answer #650081 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
John is deciding between two jobs.
\n" ); document.write( "One promises convenient hours and is closer to his home.
\n" ); document.write( "The other pays $2.25 more per hour, and John would earn $1,000 in 10 hours less
\n" ); document.write( "than it will take him to earn $900 at the first job. What is the hourly wage for each job?
\n" ); document.write( "-----
\n" ); document.write( "1st job DATA:
\n" ); document.write( "hrs = h ; rate = r ; earnings = r*h = 900
\n" ); document.write( "---
\n" ); document.write( "2nd job DATA:
\n" ); document.write( "hrs = h-10 ; rate = r+2.25 ; earn = (r+2.25)*(h-10)
\n" ); document.write( "-----
\n" ); document.write( "Equation:
\n" ); document.write( "(r+2.25)(h - 10) = 1000
\n" ); document.write( "rh - 10r + 2.25h = 1000
\n" ); document.write( "900 - 10r + 2.25h = 1000
\n" ); document.write( "2.25h = 100 + 10r
\n" ); document.write( "2.25(900/r) = 100 + 10r
\n" ); document.write( "10r^2 + 100r - 2025 = 0
\n" ); document.write( "r = $10.08
\n" ); document.write( "----
\n" ); document.write( "1st job rate = r = $10.08 per hr.
\n" ); document.write( "2nd job rate = r+2.25 = $12.33 per hr.\r
\n" ); document.write( "\n" ); document.write( "------------------
\n" ); document.write( "--------------- \n" ); document.write( "
\n" );