document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1035408>Question 1035408</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A mother is 33 years older than her twin children. In 3 years her age will be twice the combined ages of the twins. How old are the twins now? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #650050 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=650050\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let x be age of her twins and y be the age of their mother<BR>\n" );
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document.write( "1) y = x + 33<BR>\n" );
document.write( "2) y + 3 = 2(x + x +3)<BR>\n" );
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document.write( "using equation 1 substitute for y in equation 2<BR>\n" );
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document.write( "x+33 +3 = 2(2x+3)<BR>\n" );
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document.write( "x + 36 = 4x + 6<BR>\n" );
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document.write( "3x = 30<BR>\n" );
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document.write( "x = 10<BR>\n" );
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document.write( "y = 10 + 33 = 43<BR>\n" );
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document.write( "the twins are 10 years old<BR>\n" );
document.write( "their mother is 43 years old<BR>\n" );
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