document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=89281>Question 89281</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve by completing the square.  \r<BR>\n" );
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document.write( "	x^2 – 16x + 63 = 0<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #65002 by </B><A HREF=/tutors/aboutme.mpl?userid=bucky><B>bucky(2189)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=bucky><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=65002\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Given:<BR>\n" );
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document.write( "x^2 – 16x + 63 = 0<BR>\n" );
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document.write( "Solve by completing the square.<BR>\n" );
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document.write( "The first thing to do in completing the square is to make sure that the multiplier of the<BR>\n" );
document.write( "x^2 term is 1. If it is not 1, then divide the entire equation (all terms on both sides) by<BR>\n" );
document.write( "the multiplier of the x^2 term.  In this problem, the multiplier is 1 (it is 1*x^2)<BR>\n" );
document.write( "so you don't need to do anything to change it.<BR>\n" );
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document.write( "Next, I like to get rid of the constant term on the left side. In this problem you can do that<BR>\n" );
document.write( "by subtracting 63 from both sides. When you do that, the problem becomes:<BR>\n" );
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document.write( "x^2 - 16x = -63<BR>\n" );
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document.write( "Next look at the multiplier of the x term, divide it by 2, and square that result.<BR>\n" );
document.write( "Then add that number to both sides of the equation. In this problem, the multiplier<BR>\n" );
document.write( "of the x term is -16. Divide it by 2 and you get -8. Square the -8 and you get + 64. Add<BR>\n" );
document.write( "+64 to both sides of the equation and it becomes:<BR>\n" );
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document.write( "x^2 - 16x + 64 = +1<BR>\n" );
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document.write( "The left side of this equation can be factored because it is a perfect square. When you<BR>\n" );
document.write( "factor it, the number part of the factor is half of the multiplier of the x term, in<BR>\n" );
document.write( "this case half of -16 which is -8. So the equation factors to:<BR>\n" );
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document.write( "(x - 8)^2 = 1<BR>\n" );
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document.write( "Take the square root of both sides and you get:<BR>\n" );
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document.write( "x -  8 = ± 1<BR>\n" );
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document.write( "Finally, add +8 to both sides to get rid of the -8 on the left side:<BR>\n" );
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document.write( "x = 8 ± 1<BR>\n" );
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document.write( "So the two answers to this problem are x = 8 + 1 = 9 and x = 8 - 1 = 7.<BR>\n" );
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document.write( "These two answers (x = 9 and x = 7) are what you were looking to find.<BR>\n" );
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document.write( "You can check them out by multiplying (x - 9) times (x - 7) and make sure the result is<BR>\n" );
document.write( "the same as the original equation you were given.<BR>\n" );
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document.write( "Hope this process helps you to understand the process.<BR>\n" );
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