document.write( "Question 1035332: Brenda is 4 years older than walter, and carol is twice as old as brenda. three years ago, the sum of their ages was 35. How old is each now?
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Algebra.Com's Answer #649986 by stanbon(75887)\"\" \"About 
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Brenda is 4 years older than walter, and carol is twice as old as brenda. three years ago, the sum of their ages was 35. How old is each now?
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\n" ); document.write( "b = w + 4
\n" ); document.write( "c = 2b
\n" ); document.write( "b-3 + w-3 + c-3 = 35
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\n" ); document.write( "Simplify to one variable::
\n" ); document.write( "b-3 + (b-4-3) + 2b-3 = 35
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\n" ); document.write( "Solve for \"b\"::
\n" ); document.write( "4b -13 = 35
\n" ); document.write( "4b = 48
\n" ); document.write( "b = 12 (Brenda's age)
\n" ); document.write( "c = 2b = 24 (Carol's age)
\n" ); document.write( "w = b-4 = 8 (Walter's age)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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