document.write( "Question 1035332: Brenda is 4 years older than walter, and carol is twice as old as brenda. three years ago, the sum of their ages was 35. How old is each now?
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Algebra.Com's Answer #649986 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Brenda is 4 years older than walter, and carol is twice as old as brenda. three years ago, the sum of their ages was 35. How old is each now? \n" ); document.write( "------ \n" ); document.write( "b = w + 4 \n" ); document.write( "c = 2b \n" ); document.write( "b-3 + w-3 + c-3 = 35 \n" ); document.write( "--------- \n" ); document.write( "Simplify to one variable:: \n" ); document.write( "b-3 + (b-4-3) + 2b-3 = 35 \n" ); document.write( "------- \n" ); document.write( "Solve for \"b\":: \n" ); document.write( "4b -13 = 35 \n" ); document.write( "4b = 48 \n" ); document.write( "b = 12 (Brenda's age) \n" ); document.write( "c = 2b = 24 (Carol's age) \n" ); document.write( "w = b-4 = 8 (Walter's age) \n" ); document.write( "-------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "------------- \n" ); document.write( " \n" ); document.write( " |