document.write( "Question 1035330: Company is coming for dinner so the house must be spotless. Wade can clean the house in 6 hours while Sarah takes only 4 hours. Wade gets a 2 hour head start before Sarah joins him in the cleaning. If Wade starts at 11:00 am, what time will they finish cleaning? \n" ); document.write( "
Algebra.Com's Answer #649976 by josgarithmetic(39630)\"\" \"About 
You can put this solution on YOUR website!
Do this solution using time quantities and change to time line later.\r
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document.write( "            JOB/HOURS\r\n" );
document.write( "WADE         \"1%2F6\"\r\n" );
document.write( "SARAH        \"1%2F4\"\r\n" );
document.write( "BOTH         \"1%2F6%2B1%2F4\"
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\n" ); document.write( "\n" ); document.write( "The two periods of time are 2 hour and unknown t hours.
\n" ); document.write( "Those correspond to just Wade alone, and Wade plus Sarah.\r
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\n" ); document.write( "\n" ); document.write( "Uniform Work Rates Rule is RT=J to relate rate, time, and amount of job or jobs. The ONE job to be done is \"clean the house\".\r
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\n" ); document.write( "\n" ); document.write( "\"highlight%28%281%2F6%292%2B%281%2F6%2B1%2F4%29t=1%29\"------------Forming this equation is the most important part of the solution. Solving for t is the easy part. t is not \"what time\"; but it is \"how much time\".
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