document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1035325>Question 1035325</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if sec x + cos x =5/2 then find the value of sec x - cos x<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #649973 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=649973\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> if sec x + cos x =5/2 then find the value of sec x - cos x<BR>\n" );
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document.write( "Solve for cos(x)<BR>\n" );
document.write( "sec x + cos x =5/2 <BR>\n" );
document.write( "1/cos + cos = 5/2<BR>\n" );
document.write( "1 + cos^2 = 5cos/2<BR>\n" );
document.write( "2cos^2 - 5cos + 2 = 0<BR>\n" );
document.write( "(2cos - 1)(cos - 2) = 0<BR>\n" );
document.write( "cos = 2 *********** no real solution, ignore<BR>\n" );
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document.write( "cos = 1/2<BR>\n" );
document.write( "--> sec = 1/cos = 2<BR>\n" );
document.write( "--> sec - cos = 1.5\r<BR>\n" );
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