document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1035288>Question 1035288</A>: <I><SPAN STYLE=\"word-break: break-all;\"> HI!\r<BR>\n" );
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document.write( "How do I <BR>\n" );
document.write( "Find the equation of the line parallel to the line <BR>\n" );
document.write( "2x-y+=0, that passes through the point (5,2)<BR>\n" );
document.write( "Write the equation in point-slope And slope intersect forms.\r<BR>\n" );
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document.write( "Thank you , I greatly appreciate the help. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #649960 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39617)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=649960\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Part of the given equation was omitted but since wante \"parallel\", you will be able to start finding the needed equation asked as  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2x-y=2%2A5-2 ALIGN=MIDDLE  ALT=\"2x-y=2%2A5-2\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  Convert into the other two equational forms that you want.\r<BR>\n" );
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document.write( "Given equation was  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2x-y%2B4=0 ALIGN=MIDDLE  ALT=\"2x-y%2B4=0\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  It makes no difference.  The procedure can be the same.  The parallel line to it will still have the same slope and therefore the coefficients on the variables will be the same for both equations.  Find your needed equation and use you basic algebra skills to find the other two FORMS of the equation. </SPAN>\n" );
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