document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=89393>Question 89393</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Write the inverse variation equation of the following.  Y varies inversely with x and y = 9 when x = 14.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #64994 by </B><A HREF=/tutors/aboutme.mpl?userid=bucky><B>bucky(2189)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=bucky><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=64994\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The \"varies inversely with x\" means that as x gets bigger, y gets smaller and as x gets smaller,<BR>\n" );
document.write( "y gets bigger.<BR>\n" );
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document.write( "This relationship can be written as:<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y+=+k%2Fx ALIGN=MIDDLE  ALT=\"y+=+k%2Fx\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "where k is an unknown constant. Notice that as x gets bigger, the denominator of the fraction<BR>\n" );
document.write( "on the right gets bigger, so the term on the right gets smaller. Think in terms of  x being<BR>\n" );
document.write( "10. Then make x bigger, say x = 100. k divided by 10 is bigger than k divided by 100, so<BR>\n" );
document.write( "as x gets bigger, the term k divided by x (which equals y) is getting smaller.<BR>\n" );
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document.write( "For this problem you are told that when y is 9, x is 14. So in the equation that contains<BR>\n" );
document.write( "k you can substitute 9 for y and 14 for x.  When you do that the equation becomes:<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=9+=+k%2F14 ALIGN=MIDDLE  ALT=\"9+=+k%2F14\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "You can eliminate the denominator on the right side by multiplying both sides by 14 to get:<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=9+%2A+14+=+k ALIGN=MIDDLE  ALT=\"9+%2A+14+=+k\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "Multiply out the left side and the equation becomes:<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=126+=+k ALIGN=MIDDLE  ALT=\"126+=+k\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "Now you can go back to the original equation and substitute 126 for k to get the answer you<BR>\n" );
document.write( "are looking for. That answer is that the equation is:<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y+=+126%2Fx ALIGN=MIDDLE  ALT=\"y+=+126%2Fx\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "You can check this by letting x = 14 and you will get:<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y+=+126%2F14+=+9 ALIGN=MIDDLE  ALT=\"y+=+126%2F14+=+9\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "So when x = 14, obviously y = 9. After that you can let x be any value (other than zero<BR>\n" );
document.write( "because division by zero is not allowed) and you can calculate the corresponding value<BR>\n" );
document.write( "for y.  Again, you can let x be two values such as 1 and 100 and you will see that as<BR>\n" );
document.write( "x gets bigger, the value of y will vary inversely because it gets smaller.<BR>\n" );
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document.write( "Hope this helps you to understand the problem better.<BR>\n" );
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document.write( " </SPAN>\n" );
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