document.write( "Question 1035257: A 3-D painting covers a wall and the adjoining ground. The rectangular painting on the wall is 10 feet tall and 12 feet wide, and it covers the same dimensions on the ground. The wall is perpendicular to the ground. What is the distance between the top left corner of the painting on the wall (A) and the bottom right corner of the painting on the ground (B)? Round your answer to the nearest hundredth of a foot. \n" ); document.write( "
Algebra.Com's Answer #649920 by Cromlix(4381)![]() ![]() You can put this solution on YOUR website! Hi there, \n" ); document.write( "Consider labeling the painting \n" ); document.write( "on the wall ABCD \n" ); document.write( "AB being the top \n" ); document.write( "CD being the bottom \n" ); document.write( "Its corresponding part on \n" ); document.write( "the floor will be labeled \n" ); document.write( "CDEF. \n" ); document.write( "CD being the bottom of \n" ); document.write( "the wall part, but the top \n" ); document.write( "of the floor part. \n" ); document.write( "EF being the bottom of \n" ); document.write( "the floor part. \n" ); document.write( "First we calculate CF which is \n" ); document.write( "the floor diagonal. \n" ); document.write( "CE^2 + EF^2 = CF^2 \n" ); document.write( "10^2 + 12^2 = CF^2 \n" ); document.write( "CF^2 = 244 \n" ); document.write( "CF = √244 \n" ); document.write( "CF = 15.62 feet. \n" ); document.write( "Now, we use the triangle \n" ); document.write( "ACF to calculate the distance \n" ); document.write( "from the top left corner to the \n" ); document.write( "bottom right \n" ); document.write( "AC^2 + CF^2 = AF^2 \n" ); document.write( "10^2 + 15.62^2 = AF^2 \n" ); document.write( "AF = √343.9844 \n" ); document.write( "AF = 18.55 feet (2 decimal places) \n" ); document.write( "Hope this helps :-) \n" ); document.write( " |