document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=89384>Question 89384</A>: <I><SPAN STYLE=\"word-break: break-all;\"> divide 35q^9/9q^5 ÷ 25q^6/10q^5 <BR>\n" );
document.write( "a. 18/175q<BR>\n" );
document.write( "b. 175q^4/18<BR>\n" );
document.write( "c. 9q^6/14<BR>\n" );
document.write( "d. 14q^2/9 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #64989 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=64989\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (35Q^9/9Q^5)/(25Q^6/10Q^5) TAKING THESE TERMS SEPARATELY WE HAVE:<BR>\n" );
document.write( "35Q^9/9Q^5=35Q^4/9 &<BR>\n" );
document.write( "25Q^6/10Q^5=5Q/2 NOW WE INVERT THE SECOND TERM & MULTIPLY.<BR>\n" );
document.write( "(35Q^4/9)(2/5Q)=(7Q^3*2)/9=14Q^3/9 ANSWER. </SPAN>\n" );
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