document.write( "Question 89397This question is from textbook Beginning Algebra
\n" ); document.write( ": Solve the quadratice equation by completing the square:
\n" ); document.write( "x^2 - 6x - 3 = 0
\n" ); document.write( "x^2 - 6x = 3
\n" ); document.write( "x - 6x + 9 = 3
\n" ); document.write( "(x-3)^2 = 3
\n" ); document.write( "x - 3 = +/- radical 3
\n" ); document.write( "x = 3 +/- radical 3\r
\n" ); document.write( "\n" ); document.write( "Is this correct?
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Algebra.Com's Answer #64987 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
There is an error on the step where you add 9 to the left side\r
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\n" ); document.write( "\n" ); document.write( "\"x+-+6x+%2B+9+=+3\"\r
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\n" ); document.write( "\n" ); document.write( "You need to add 9 to both sides to balance the equation\r
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\n" ); document.write( "\n" ); document.write( "\"x+-+6x+%2B+9+=+3+%2B+highlight%289%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+-+6x+%2B+9+=+12\" Add\r
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\n" ); document.write( "\n" ); document.write( "\"%28x-3%29%5E2=+12\" Factor the left side\r
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\n" ); document.write( "\n" ); document.write( "\"x-3=0%2B-+sqrt%2812%29\" Take the square root of both sides\r
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\n" ); document.write( "\n" ); document.write( "\"x=3%2B-+sqrt%2812%29\" Add 3 to both sides\r
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\n" ); document.write( "\n" ); document.write( "\"x=3%2B-+2%2Asqrt%283%29\" Simplify the square root (note: If you need help with simplifying the square root, check out this solver)
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