document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1035192>Question 1035192</A>: <I><SPAN STYLE=\"word-break: break-all;\"> what is the answer to A grocer has two kinds of nuts. one costs $5/kg another costs $4.20/kg how many kilograms of each type should be mixed in order to get 60 kg of a mixture worth $4.80 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #649843 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=649843\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let nuts at 5 be x and nuts at 4.20 be y<BR>\n" );
document.write( "x+y = 60 subtract x on both sides<BR>\n" );
document.write( "x-x+y = 60-x<BR>\n" );
document.write( "y = 60-x We'll use this value for y next<BR>\n" );
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document.write( "5x+4.20y = 4.80(60) substitute for y:<BR>\n" );
document.write( "5x+4.20(60-x) = 4.80(60)<BR>\n" );
document.write( "5x+252-4.20x = 288<BR>\n" );
document.write( "0.80x = 36<BR>\n" );
document.write( "x = 45<BR>\n" );
document.write( "You need 45kg of $5 nuts and 60-45 = 15kg of $4.20 nuts<BR>\n" );
document.write( "John </SPAN>\n" );
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