document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1035183>Question 1035183</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Mr. Martin traveled to a city 350 miles from his home to attend a meeting.  Due to car trouble, his average speed returning was 11 mph less than his speed going.  If the total time for the round trip was 18 hours, at what rate of speed did he travel to the city? (Round your answer to the nearest tenth.) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #649842 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel555><B>jorel555(1290)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel555><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=649842\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let n= speed on return trip. Then traveling to speed is n+11. So:<BR>\n" );
document.write( "350/n+350/n+11=18<BR>\n" );
document.write( "350(n+11)+350n=18(n^2+11n)<BR>\n" );
document.write( "350n+350n+3850=18n^2+198n<BR>\n" );
document.write( "18n^2-502n-3850=0<BR>\n" );
document.write( "Using the quadratic formula, n=34.15. N+11=45.15!!!!!!!! </SPAN>\n" );
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