document.write( "Question 89372: Solve by using the quadratic formula\r
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Algebra.Com's Answer #64978 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Let's use the quadratic formula to solve for x:\r
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\n" ); document.write( "\n" ); document.write( "Starting with the general quadratic\r
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\n" ); document.write( "\n" ); document.write( "\"ax%5E2%2Bbx%2Bc=0\"\r
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\n" ); document.write( "\n" ); document.write( "the general solution using the quadratic equation is:\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29\"\r
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\n" ); document.write( "\n" ); document.write( "So lets solve \"4%2Ax%5E2-3%2Ax%2B3=0\" ( notice \"a=4\", \"b=-3\", and \"c=3\")\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28--3+%2B-+sqrt%28+%28-3%29%5E2-4%2A4%2A3+%29%29%2F%282%2A4%29\" Plug in a=4, b=-3, and c=3\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%283+%2B-+sqrt%28+%28-3%29%5E2-4%2A4%2A3+%29%29%2F%282%2A4%29\" Negate -3 to get 3\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%283+%2B-+sqrt%28+9-4%2A4%2A3+%29%29%2F%282%2A4%29\" Square -3 to get 9 (note: remember when you square -3, you must square the negative as well. This is because \"-3%5E2=-3%2A-3=9\".)\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%283+%2B-+sqrt%28+9%2B-48+%29%29%2F%282%2A4%29\" Multiply \"-4%2A3%2A4\" to get \"-48\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%283+%2B-+sqrt%28+-39+%29%29%2F%282%2A4%29\" Combine like terms in the radicand (everything under the square root)\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%283+%2B-+i%2Asqrt%2839%29%29%2F%282%2A4%29\" Simplify the square root (note: since we cannot take the square root of a negative value, we must factor \"sqrt%28-39%29\" to \"i%2Asqrt%2839%29\" to make the radicand positive. If you need help with simplifying the square root, check out this solver)\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%283+%2B-+i%2Asqrt%2839%29%29%2F%288%29\" Multiply 2 and 4 to get 8\r
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\n" ); document.write( "\n" ); document.write( "After simplifying, the quadratic has roots of\r
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\n" ); document.write( "\n" ); document.write( "\"x=3%2F8+%2B+sqrt%2839%29%2F8%2Ai\" or \"x=3%2F8+-+sqrt%2839%29%2F8%2Ai\"\r
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\n" ); document.write( "\n" ); document.write( "Notice if we graph the quadratic \"y=4%2Ax%5E2-3%2Ax%2B3\", we get\r
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\n" ); document.write( "\n" ); document.write( "\"+graph%28+500%2C+500%2C+-14.625%2C+15.375%2C+-12.5625%2C+17.4375%2C+4%2Ax%5E2-3%2Ax%2B3%29+\" graph of \"y=4%2Ax%5E2-3%2Ax%2B3\"\r
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\n" ); document.write( "\n" ); document.write( "To visually verify the answer, check out this page to see a visual representation of imaginary roots
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