document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1035152>Question 1035152</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A chemist has a solution which is 60% pure acid and another solution which is 35% pure acid.  How many grams of the 35% solution should he use to make 3000 grams of a solution which is 50% pure acid? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #649769 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=649769\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x be the number of grams of 35% solution the chemist needs.<BR>\n" );
document.write( "Then the number of grams of 60% solution would be 3000-x.<BR>\n" );
document.write( "The set up looks like this:<BR>\n" );
document.write( ".35x + .60(3000-x) = .50(3000)<BR>\n" );
document.write( "Now solve for x...<BR>\n" );
document.write( ".35x + 1800 - .60x = 1500<BR>\n" );
document.write( "-.25x = -300<BR>\n" );
document.write( "x = 1200 grams of 35% solution </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );