document.write( "Question 89373: Solve by completing the square.\r
\n" ); document.write( "\n" ); document.write( "4x^2+2x-3=0\r
\n" ); document.write( "\n" ); document.write( "Thanks for any help.
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Algebra.Com's Answer #64973 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
\"4x%5E2+%2B+2x+-+3+=+0\"
\n" ); document.write( "First, divide both sides by 4
\n" ); document.write( "\"x%5E2+%2B+%281%2F2%29x+-+3%2F4+=+0\"
\n" ); document.write( "Add 3/4 to both sides
\n" ); document.write( "\"x%5E2+%2B+%281%2F2%29x+=+3%2F4\"
\n" ); document.write( "Now, take 1/2 of the coefficient of x, square it, add it to both sides
\n" ); document.write( "\"%281%2F2%29%2F2+=+1%2F4\" and \"%281%2F4%29%5E2+=+1%2F16\"
\n" ); document.write( "\"x%5E2+%2B+%281%2F2%29x+%2B+1%2F16+=+3%2F4+%2B+1%2F16\"
\n" ); document.write( "\"%28x+%2B+1%2F4%29%5E2+=+12%2F16+%2B+1%2F16\"
\n" ); document.write( "\"%28x+%2B+1%2F4%29%5E2+=+13%2F16\"
\n" ); document.write( "Take the square root of both sides
\n" ); document.write( "\"x+%2B+1%2F4+=+sqrt%2813%29+%2F+4\"
\n" ); document.write( "\"x+=+sqrt%2813%29%2F4+-+1%2F4\"
\n" ); document.write( "\"x+=+%28sqrt%2813%29+-+1%29%2F4\"
\n" ); document.write( "answer
\n" ); document.write( "You can check this by subbing it back into original
\n" ); document.write( "equation for x
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