document.write( "Question 1035047: If $100 is invested at 4% compounded quarterly, what is the interest earned after:
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document.write( "3 years(interest earned)=
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document.write( "5 years(interest earned)= \n" );
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Algebra.Com's Answer #649713 by Theo(13342)![]() ![]() You can put this solution on YOUR website! f = p * (1+r)^n \n" ); document.write( "f is the future value \n" ); document.write( "p is the present value \n" ); document.write( "r is the interest rate per time period. \n" ); document.write( "n is the number of time periods.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "with quarterly compounding, the time period is 1 quarter.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( ".04 per year / 4 = .01 interest rate per quarter. \n" ); document.write( "3 years * 4 = 12 quarters. \n" ); document.write( "5 years * 4 = 20 quarters.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "p = 100\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "f = p * (1+r)^n for p = 100 and r = .01 and n = 12 becomes: \n" ); document.write( "f = 100 * (1.01)^12 which becomes: \n" ); document.write( "f = 112.682503.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "f = p * (1+r)^n for p = 100 and r = .01 and n = 20 becomes: \n" ); document.write( "f = 100 * (1.01)^20 which becomes: \n" ); document.write( "f = 122.019004\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |