document.write( "Question 89374: Find the x intercepts\r
\n" ); document.write( "\n" ); document.write( "y=x^2-2x+4\r
\n" ); document.write( "\n" ); document.write( "Thanks for any help
\n" ); document.write( "

Algebra.Com's Answer #64971 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
The x-intercepts are where y = 0
\n" ); document.write( "\"y+=+x%5E2+-+2x+%2B+4\"
\n" ); document.write( "\"x%5E2+-+2x+%2B+4+=+0\"
\n" ); document.write( "\"x%5E2+-+2x+=+-4\"
\n" ); document.write( "add 1 to both sides
\n" ); document.write( "\"x%5E2+-+2x+%2B+1+=+-4+%2B+1\"
\n" ); document.write( "\"%28x-1%29%5E2+=+-3\"
\n" ); document.write( "I need to take the square root of both sides, but
\n" ); document.write( "I can't because the square root of -3 is imaginary,
\n" ); document.write( "so there are no x-intercepts
\n" ); document.write( "Here is the graph. You can see that it never touches
\n" ); document.write( "the x-axis
\n" ); document.write( "\"+graph%28+400%2C+400%2C+-5%2C+10%2C+-5%2C+20%2C+x%5E2+-+2x+%2B+4%29+\"
\n" ); document.write( "
\n" );