document.write( "Question 1035086: Distance between the lines 5x+12y-1=0 and 10x+24y+k=0 is 2 then the value of k is \n" ); document.write( "
Algebra.Com's Answer #649706 by josgarithmetic(39620)\"\" \"About 
You can put this solution on YOUR website!
Change this description a little bit. The slopes of both lines must be \"5%2F12\" for the description to be meaningful. The two equations of these lines are then 5x+12y-1=0 and 5x+12y+j=0, and you want to find j. The two lines are parallel, and the distance between them is 2.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Here is 5x+12y-1=0 graphed:
\n" ); document.write( "\"graph%28300%2C300%2C-3%2C4%2C-3%2C4%2C-5x%2F12%2B1%2F12%29\"
\n" ); document.write( "The equation can also be stated \"y=-%285%2F12%29x%2B1%2F12\".\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Choose a convenient point on this line, maybe the x-intercept, ( 1/5 ,0).\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "You want the other line, \"5x%2B12y%2Bj=0\", to be 2 unit away from 5x+12y-1=0; and you can pick either above OR below. Put the equation of the line you wish to find in slope-intercept form, as \"y=-%285%2F12%29x-j%2F12\".\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Summarizing all this, we want distance from \"y=-%285%2F12%29x%2B1%2F12\" to \"y=-%285%2F12%29x-j%2F12\" to be equal to 2. To be much more specific, referring to a given or desired point on the first line graphed, we want the distance between ( 1/5, 0 ) and \"y=-%285%2F12%29x%2Bj%2F12\" to be equal to 2.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "...
\n" ); document.write( "Keep reading and thinking on that.
\n" ); document.write( "A general point for the equation of the line you want to find is an ordered pair point ( x, -(5/12)x+j/12 ).
\n" ); document.write( "When you have this then use the distance formula to set up the equation necessary to solve for j.
\n" ); document.write( "
\n" );