document.write( "Question 1035084: Elaine has 88 coins in a purse which are all 5-cent coins and 10-cent coins. The total value of the coins are $7. How many of each type of coin does she have
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Algebra.Com's Answer #649704 by ikleyn(52863)\"\" \"About 
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\n" ); document.write( "Elaine has 88 coins in a purse which are all 5-cent coins and 10-cent coins. The total value of the coins are $7.
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document.write( "Let n be the number of nickels (5-cent coins) Elain has.\r\n" );
document.write( "Then the number of dimes (10-cent coins) is (88-n).\r\n" );
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document.write( "   n   nickels contribute 5n cents into the total.\r\n" );
document.write( "(88-n) dimes   contribute 10*(88-n) cents into the total.\r\n" );
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document.write( "So, you have this \"value\" equation\r\n" );
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document.write( "5n + 10*(88-n) = 700   cents.\r\n" );
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document.write( "Simplify and solve:\r\n" );
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document.write( "5n + 880 - 10n = 700,  or\r\n" );
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document.write( "-5n = 700 - 880,\r\n" );
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document.write( "-5n = -180,\r\n" );
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document.write( "n = \"%28-180%29%2F%28-5%29\" = \"180%2F5\" = 36.\r\n" );
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document.write( "So, Elaine has 36 nickels (5-sent coins) and 88-36 = 52 dimes (10-cent coins).\r\n" );
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document.write( "Check. 5*36 + 10*52 = 180 + 520 = 700 cents.   Correct!\r\n" );
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