document.write( "Question 1034987: It took a crew 8 h 32 min to row 8 km upstream and back again. If the rate of flow of the stream was 7 km/h, what was the rowing speed of the crew in still water? \n" ); document.write( "
Algebra.Com's Answer #649673 by ankor@dixie-net.com(22740)\"\" \"About 
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It took a crew 8 h 32 min to row 8 km upstream and back again.
\n" ); document.write( " If the rate of flow of the stream was 7 km/h, what was the rowing speed of the crew in still water?
\n" ); document.write( ":
\n" ); document.write( "Let s = rowing speed in still water.
\n" ); document.write( "then
\n" ); document.write( "(s-7) = effective speed upstream
\n" ); document.write( "and
\n" ); document.write( "(s+7) = effective speed downstream
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\n" ); document.write( "Change 8 hrs 32 min to hrs: 8 + 32/60 = 8 + 8/15 hrs = 128/15
\n" ); document.write( ":
\n" ); document.write( " write a time equation, time = dist/speed
\n" ); document.write( "Time up + time down = 8hr 32 min
\n" ); document.write( "\"8%2F%28%28s-7%29%29\" + \"8%2F%28%28s%2B7%29%29\" = \"128%2F15\"
\n" ); document.write( "simplify, divide by 8
\n" ); document.write( "\"1%2F%28%28s-7%29%29\" + \"1%2F%28%28s%2B7%29%29\" = \"16%2F15\"
\n" ); document.write( "multiply by 15(s-7)(s+7), cancel the denominators
\n" ); document.write( " 15(s+7) + 15(s-7) = (s-7)(s+7)*16
\n" ); document.write( " 15s + 105 + 15s - 105 = 16(s^2 - 49)
\n" ); document.write( " 30s = 16s^2 - 784
\n" ); document.write( "0 = 16s^2 - 30s - 784
\n" ); document.write( "simplify, divide by 2
\n" ); document.write( "8s^2 - 15s - 392 = 0
\n" ); document.write( "you can use the quadratic formula, but this will factor to
\n" ); document.write( "(8s+49)(s-8) = 0
\n" ); document.write( "the positive solution is all we want here
\n" ); document.write( "s = 8 km/hr in still water
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\n" ); document.write( "See if that checks out. Find the actual time each way
\n" ); document.write( "8/(8-7) = 8 hrs upstream
\n" ); document.write( "8/(8+7) = .533 hrs which is 32 min down stream
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