document.write( "Question 1034986: A salesman drives from Ajax to Barrington, a distance of 114 mi, at a steady speed. He then increases his speed by 14 mi/h to drive the 141 mi from Barrington to Collins. If the second leg of his trip took 3 min more time than the first leg, how fast was he driving between Ajax and Barrington? \n" ); document.write( "
Algebra.Com's Answer #649637 by ankor@dixie-net.com(22740)\"\" \"About 
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A salesman drives from Ajax to Barrington, a distance of 114 mi, at a steady speed.
\n" ); document.write( " He then increases his speed by 14 mi/h to drive the 141 mi from Barrington to Collins.
\n" ); document.write( " If the second leg of his trip took 3 min more time than the first leg, how fast was he driving between Ajax and Barrington?
\n" ); document.write( ":
\n" ); document.write( "A-------114------B--------141---------C
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\n" ); document.write( "Let s = his speed from A to B
\n" ); document.write( "then
\n" ); document.write( "(s+14) = his speed from B to C
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\n" ); document.write( "Change 3 min to hrs: 3/60 reduces to 1/20
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\n" ); document.write( "Write a time equation; time = dist/speed
\n" ); document.write( "AB time - BC time = 3 min
\n" ); document.write( "\"141%2F%28%28s%2B14%29%29\" - \"114%2Fs\" = \"1%2F20\"
\n" ); document.write( "multiply equation by 20s(s+14), cancel the denominators and you have
\n" ); document.write( "20s(141) - 20(s+14)(114) = s(s+14)
\n" ); document.write( "20s(141) - 2280(s+14) = s(s+14)
\n" ); document.write( "2820s - 2280s - 31920 = s^2 + 14s
\n" ); document.write( "540s - 31920 = s^2 + 14s
\n" ); document.write( "A quadratic equation
\n" ); document.write( "0 = s^2 + 14s - 540s + 31920
\n" ); document.write( "s^2 - 526s + 31920 = 0
\n" ); document.write( "The quadratic formula; a=1; b=-426; c=31920; reveals two solutions
\n" ); document.write( "s = 456, not reasonable in a car
\n" ); document.write( "and
\n" ); document.write( "s = 70 mph is the speed from A to B
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\n" ); document.write( "See if that checks out, find the actual time for each part (BC is 84mph)
\n" ); document.write( "141/84 = 1.67857 hrs
\n" ); document.write( "114/70 = 1.62857 hrs
\n" ); document.write( "--------------------
\n" ); document.write( "difference: .05 hrs; which is 3 min. (3/60 = .05)
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\n" ); document.write( "Hey, did this make sense to you? I like to know if I am explaining this sufficiently. Thanks. CK
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